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<article> <h1>談?wù)勛杩蛊ヅ涞睦斫?/h1> <div id="xxzfhrn" class="authorTimeSource"> <span>作者：</span> <span>時(shí)間：2016-04-16</span> <span>來源：網(wǎng)絡(luò)</span> <link rel="stylesheet" type="text/css"/> <span style="float:right; width:130px;margin-right:0px; text-align:right;"> <div id="9jpxn1j" class="nav0"> <ul> <li><a href="javascript:void(0);"><img src="http://www.ex-cimer.com/event/action/images/icon_add_4.png" width="20" border="0" align="absmiddle" />加入技術(shù)交流群</a> <ul> <li style="text-align:center;"><img src="http://www.ex-cimer.com/event/company/images/code_1.jpg" width="130"><br />掃碼加入<br />和技術(shù)大咖面對面交流<br />海量資料庫查詢</li> </ul> </li> </ul> </div> </span> <span style="float:right; width:30px;margin-right:0px; text-align:right;"><a rel="nofollow">收藏</a></span> </div> <div id="793vrph" class="hAd4_Afinal20a_back">  <iframe id='a890e388' name='a890e388' src='https://ad.eepw.com.cn/www/delivery/afr.php?zoneid=88&cb=INSERT_RANDOM_NUMBER_HERE' frameborder='0' scrolling='no' width='660' height='60'><a target='_blank'><img src='https://ad.eepw.com.cn/www/delivery/avw.php?zoneid=88&cb=INSERT_RANDOM_NUMBER_HERE&n=a635e61e' border='0' alt='' /></a></iframe> </div> <div style="margin-top:28px;"></div> <div id="jtj9hhz" class="content" id="contentDiv" style="position:relative;"> <div id="57319vl" class="ad_300x180_Afinal13_back">  <iframe id='a225770a' name='a225770a' src='https://ad.eepw.com.cn/www/delivery/afr.php?zoneid=87&cb=INSERT_RANDOM_NUMBER_HERE' frameborder='0' scrolling='no' width='300' height='200'><a target='_blank'><img src='https://ad.eepw.com.cn/www/delivery/avw.php?zoneid=87&cb=INSERT_RANDOM_NUMBER_HERE&n=a576c0a2' border='0' alt='' /></a></iframe> </div> <span id="contentlabels" style="font-size:14px;"><p>　　<a class="contentlabel" href="http://www.ex-cimer.com/news/listbylabel/label/阻抗匹配"><em>阻抗匹配</em></a>是指信號(hào)源或者傳輸線跟負(fù)載之間的一種合適的搭配方式。<a class="contentlabel" href="http://www.ex-cimer.com/news/listbylabel/label/阻抗匹配"><em>阻抗匹配</em></a>分為低頻和高頻兩種情況討論。我們先從直流電壓源驅(qū)動(dòng)一個(gè)負(fù)載入手。由于實(shí)際的電壓源，總是有內(nèi)阻的，我們可以把一個(gè)實(shí)際電壓源，等效成一個(gè)理想的電壓源跟一個(gè)電阻r串聯(lián)的模型。假設(shè)負(fù)載電阻為R，電源電動(dòng)勢為U，內(nèi)阻為r，那么我們可以計(jì)算出流過電阻R的電流為：I=U/(R+r)，可以看出，負(fù)載電阻R越小，則輸出電流越大。負(fù)載R上的電壓為：Uo=IR=U/[1+(r/R)]，可以看出，負(fù)載電阻R越大，則輸出電壓Uo越高。再來計(jì)算一下電阻R消耗的功率為：</p>本文引用地址：<a href="http://www.ex-cimer.com/article/201604/289790.htm">http://www.ex-cimer.com/article/201604/289790.htm</a><p>　　P=I2×R=[U/(R+r)]2×R=U2×R/(R2+2×R×r+r2)</p><p>　　=U2×R/[(R-r)2+4×R×r]</p><p>　　=U2/{[(R-r)2/R]+4×r}</p><p>　　對于一個(gè)給定的信號(hào)源，其內(nèi)阻r是固定的，而負(fù)載電阻R則是由我們來選擇的。注意式中[(R-r)2/R]，當(dāng)R=r時(shí)，[(R-r)2/R]可取得最小值0，這時(shí)負(fù)載電阻R上可獲得最大輸出功率Pmax=U2/(4×r)。即，當(dāng)負(fù)載電阻跟信號(hào)源內(nèi)阻相等時(shí)，負(fù)載可獲得最大輸出功率，這就是我們常說的<a class="contentlabel" href="http://www.ex-cimer.com/news/listbylabel/label/阻抗匹配"><em>阻抗匹配</em></a>之一。此結(jié)論同樣適用于低頻電路及高頻電路。當(dāng)交流電路中含有容性或感性阻抗時(shí)，結(jié)論有所改變，就是需要信號(hào)源與負(fù)載阻抗的的實(shí)部相等，虛部互為相反數(shù)，這叫做共扼匹配。在低頻電路中，我們一般不考慮傳輸線的匹配問題，只考慮信號(hào)源跟負(fù)載之間的情況，因?yàn)榈皖l信號(hào)的波長相對于傳輸線來說很長，傳輸線可以看成是“短線”，反射可以不考慮(可以這么理解：因?yàn)榫€短，即使反射回來，跟原信號(hào)還是一樣的)。從以上分析我們可以得出結(jié)論：如果我們需要輸出電流大，則選擇小的負(fù)載R;如果我們需要輸出電壓大，則選擇大的負(fù)載R;如果我們需要輸出功率最大，則選擇跟信號(hào)源內(nèi)阻匹配的電阻R。有時(shí)阻抗不匹配還有另外一層意思，例如一些儀器輸出端是在特定的負(fù)載條件下設(shè)計(jì)的，如果負(fù)載條件改變了，則可能達(dá)不到原來的性能，這時(shí)我們也會(huì)叫做阻抗失配。</p><p>　　在高頻電路中，我們還必須考慮反射的問題。當(dāng)信號(hào)的頻率很高時(shí)，則信號(hào)的波長就很短，當(dāng)波長短得跟傳輸線長度可以比擬時(shí)，反射信號(hào)疊加在原信號(hào)上將會(huì)改變原信號(hào)的形狀。如果傳輸線的特征阻抗跟負(fù)載阻抗不相等(即不匹配)時(shí)，在負(fù)載端就會(huì)產(chǎn)生反射。為什么阻抗不匹配時(shí)會(huì)產(chǎn)生反射以及特征阻抗的求解方法，牽涉到二階偏微分方程的求解，在這里我們不細(xì)說了，有興趣的可參看電磁場與微波方面書籍中的傳輸線理論。傳輸線的特征阻抗(也叫做特性阻抗)是由傳輸線的結(jié)構(gòu)以及材料決定的，而與傳輸線的長度，以及信號(hào)的幅度、頻率等均無關(guān)。</p><p>　　例如，常用的閉路電視同軸電纜特性阻抗為75Ω，而一些射頻設(shè)備上則常用特征阻抗為50Ω的同軸電纜。另外還有一種常見的傳輸線是特性阻抗為300Ω的扁平平行線，這在農(nóng)村使用的電視天線架上比較常見，用來做八木天線的饋線。因?yàn)殡娨暀C(jī)的射頻輸入端輸入阻抗為75Ω，所以300Ω的饋線將與其不能匹配。實(shí)際中是如何解決這個(gè)問題的呢?不知道大家有沒有留意到，電視機(jī)的附件中，有一個(gè)300Ω到75Ω的阻抗轉(zhuǎn)換器(一個(gè)塑料封裝的，一端有一個(gè)圓形的插頭的那個(gè)東東，大概有兩個(gè)大拇指那么大)。它里面其實(shí)就是一個(gè)傳輸線變壓器，將300Ω的阻抗，變換成75Ω的，這樣就可以匹配起來了。這里需要強(qiáng)調(diào)一點(diǎn)的是，特性阻抗跟我們通常理解的電阻不是一個(gè)概念，它與傳輸線的長度無關(guān)，也不能通過使用歐姆表來測量。為了不產(chǎn)生反射，負(fù)載阻抗跟傳輸線的特征阻抗應(yīng)該相等，這就是傳輸線的阻抗匹配，如果阻抗不匹配會(huì)有什么不良后果呢?如果不匹配，則會(huì)形成反射，能量傳遞不過去，降低效率;會(huì)在傳輸線上形成駐波(簡單的理解，就是有些地方信號(hào)強(qiáng)，有些地方信號(hào)弱)，導(dǎo)致傳輸線的有效功率容量降低;功率發(fā)射不出去，甚至?xí)p壞發(fā)射設(shè)備。如果是電路板上的高速信號(hào)線與負(fù)載阻抗不匹配時(shí)，會(huì)產(chǎn)生震蕩，輻射干擾等。</p><p>　　當(dāng)阻抗不匹配時(shí)，有哪些辦法讓它匹配呢?第一，可以考慮使用變壓器來做阻抗轉(zhuǎn)換，就像上面所說的電視機(jī)中的那個(gè)例子那樣。第二，可以考慮使用串聯(lián)/并聯(lián)電容或電感的辦法，這在調(diào)試射頻電路時(shí)常使用。第三，可以考慮使用串聯(lián)/并聯(lián)電阻的辦法。一些驅(qū)動(dòng)器的阻抗比較低，可以串聯(lián)一個(gè)合適的電阻來跟傳輸線匹配，例如高速信號(hào)線，有時(shí)會(huì)串聯(lián)一個(gè)幾十歐的電阻。而一些接收器的輸入阻抗則比較高，可以使用并聯(lián)電阻的方法，來跟傳輸線匹配，例如，485<a class="contentlabel" href="http://www.ex-cimer.com/news/listbylabel/label/總線"><em>總線</em></a>接收器，常在數(shù)據(jù)線終端并聯(lián)120歐的匹配電阻。(始端串聯(lián)匹配，終端并聯(lián)匹配)</p><p>　　為了幫助大家理解阻抗不匹配時(shí)的反射問題，我來舉兩個(gè)例子：假設(shè)你在練習(xí)拳擊——打沙包。如果是一個(gè)重量合適的、硬度合適的沙包，你打上去會(huì)感覺很舒服。但是，如果哪一天我把沙包做了手腳，例如，里面換成了鐵沙，你還是用以前的力打上去，你的手可能就會(huì)受不了了——這就是負(fù)載過重的情況，會(huì)產(chǎn)生很大的反彈力。相反，如果我把里面換成了很輕很輕的東西，你一出拳，則可能會(huì)撲空，手也可能會(huì)受不了——這就是負(fù)載過輕的情況。</p></span>  <div class="zrzpzzf" id="coverDiv" class="article_reg" style="width:100%;overflow:hidden;display:none;z-index:10;position:absolute;left:0;background:#fff;"> <center> <img src="https://webstorage.eepw.com.cn/images/display/reg.jpg" border="0" usemap="#Map" /> <map name="Map" id="Map"> <area shape="rect" coords="133,235,319,253" target="_blank" /> <area shape="rect" coords="132,315,319,335" /> </map> </center> </div>  <span id="9b9r7lr" class="hAd8"> <br></span>   </div> </article> <div id="btvf9jj" class="clear"></div> <br/> <div id="pz33xfv" 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