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          EEPW首頁 > 嵌入式系統(tǒng) > 設(shè)計(jì)應(yīng)用 > 26. 點(diǎn)陣式LED簡(jiǎn)單圖形顯示技術(shù)

          26. 點(diǎn)陣式LED簡(jiǎn)單圖形顯示技術(shù)

          作者: 時(shí)間:2016-11-18 來源:網(wǎng)絡(luò) 收藏
          1.實(shí)驗(yàn)任務(wù)
          在8X8點(diǎn)陣式LED顯示“★”、“●”和心形圖,通過按鍵來選擇要顯示的圖形。
          2.電路原理

          圖4.26.1
          3.硬件系統(tǒng)連線
          (1).把“單片機(jī)系統(tǒng)”區(qū)域中的P1端口用8芯排芯連接到“點(diǎn)陣模塊”區(qū)域中的“DR1-DR8”端口上;
          (2).把“單片機(jī)系統(tǒng)”區(qū)域中的P3端口用8芯排芯連接到“點(diǎn)陣模塊”區(qū)域中的“DC1-DC8”端口上;
          (3).把“單片機(jī)系統(tǒng)”區(qū)域中的P2.0/A8端子用導(dǎo)線連接到“獨(dú)立式鍵盤”區(qū)域中的SP1端子上;
          4.程序設(shè)計(jì)內(nèi)容

          5.匯編源程序
          CNTAEQU30H
          COUNTEQU31H

          ORG00H
          LJMPSTART
          ORG0BH
          LJMPT0X
          ORG30H
          START:MOVCNTA,#00H
          MOVCOUNT,#00H
          MOVTMOD,#01H
          MOVTH0,#(65536-4000)/256
          MOVTL0,#(65536-4000)MOD256
          SETBTR0
          SETBET0
          SETBEA
          WT:JBP2.0,WT
          MOVR6,#5
          MOVR7,#248
          D1:DJNZR7,$
          DJNZR6,D1
          JBP2.0,WT
          INCCOUNT
          MOVA,COUNT
          CJNEA,#03H,NEXT
          MOVCOUNT,#00H
          NEXT:JNBP2.0,$
          SJMPWT

          T0X:NOP
          MOVTH0,#(65536-4000)/256
          MOVTL0,#(65536-4000)MOD256
          MOVDPTR,#TAB
          MOVA,CNTA
          MOVCA,@A+DPTR
          MOVP3,A
          MOVDPTR,#GRAPH
          MOVA,COUNT
          MOVB,#8
          MULAB
          ADDA,CNTA
          MOVCA,@A+DPTR
          MOVP1,A
          INCCNTA
          MOVA,CNTA
          CJNEA,#8,NEX
          MOVCNTA,#00H
          NEX:RETI

          TAB:DB0FEH,0FDH,0FBH,0F7H,0EFH,0DFH,0BFH,07FH
          GRAPH:DB12H,14H,3CH,48H,3CH,14H,12H,00H
          DB00H,00H,38H,44H,44H,44H,38H,00H
          DB30H,48H,44H,22H,44H,48H,30H,00H
          END

          6.C語言源程序
          #include

          unsignedcharcodetab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
          unsignedcharcodegraph[3][8]={{0x12,0x14,0x3c,0x48,0x3c,0x14,0x12,0x00},
          {0x00,0x00,0x38,0x44,0x44,0x44,0x38,0x00},
          {0x30,0x48,0x44,0x22,0x44,0x48,0x30,0x00}
          };
          unsignedcharcount;
          unsignedcharcnta;

          voidmain(void)
          {
          unsignedchari,j;

          TMOD=0x01;
          TH0=(65536-4000)/256;
          TL0=(65536-4000)%256;
          TR0=1;
          ET0=1;
          EA=1;

          while(1)
          {
          if(P2_0==0)
          {
          for(i=5;i>0;i--)
          for(j=248;j>0;j--);
          if(P2_0==0)
          {
          count++;
          if(count==3)
          {
          count=0;
          }
          while(P2_0==0);
          }
          }
          }
          }

          voidt0(void)interrupt1using0
          {
          TH0=(65536-4000)/256;
          TL0=(65536-4000)%256;
          P3=tab[cnta];
          P1=graph[count][cnta];
          cnta++;
          if(cnta==8)
          {
          cnta=0;
          }
          }


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